获取ajax的错误信息 传回2个参数

  $.ajax({
                    type: "post",
                    url: "../api/buysellfive.ashx",
                    data: "provinceid=" + $('#vstockcode').val(),
                    success: function (data) {
                        var a = data.split("|");//传回值用“|”隔开
//                        alert(a[0]);
//                        alert(a[1]);
                        $("#buy1").html(a[0]);
                        $("#_maxcont").html(a[1]);                                     
                        //alert(data);
                    },
                    error: function (xhr, type, exception) {//获取ajax的错误信息
                        alert(xhr.responseText, "Failed");
                    }
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